Inverse functions
Inverse functions
This area takes functions, but where we usually take values of x and look at the corresponding values of f(x), here we take values of f(x) and look at what value of x produces this.
Inverse functions with one to one mapping
Let's look at an example:
If we have the function, f: x → 3x, and the 'domain' x ∈ {1, 2, 3}
Then we see the mappings are for this function over these x values is:
So now we have the mapping of x to f(x). But we can also go backwards and map the range values (i.e. the values produced by f(x)) to those in the domain (i.e. the values of x used).
| So forward mapping gives |
| 1 → 3 |
| 2 → 6 |
| 3 → 9 |
| And inverse mapping gives |
| 3 → 1 |
| 6 → 2 |
| 9 → 3 |
Looking at the inverse mapping, the values produced can also be written as another function:
x → x/3, where x → {3, 6, 9}.
This reverse mapping is a one-to-one mapping and is called the inverse function of f where f: x → 3x.
The symbol for any inverse is f−1.
| So, f−1 | x → x/3, | x ∈ {3, 6, 9} |
| is the inverse of f | x → 3x, | x ∈ {1, 2, 3} |
The relationship between the graphs of f and the inverse f−1 is shown in the diagram:
From the diagrams you can see that the transformation to get from f(x) to f−1(x) is a reflection in the line y = x.
This helps us to find the inverse of more complicated functions, and we do so by:
Writing the equation as y = f(x).
Swapping the letters x and y. (This is the same as reflecting in the line y = x.)
Rearranging the formula into a new y = f(x). This is the inverse function.
Example:
Find the inverse function of


Therefore:

Rearrange to get,
xy + 2x = y
2x = y(1 − x)

This means that the inverse function is,

The above example had a 'one to one' mapping (see lesson 1 - mapping). If you have a one to many mapping this causes complications.
This is because a single value of f(x) can be generated from many different values of x and this cannot be defined using a single inverse function. The way we can get around this is to set the domain (the range of x values the function can use), such that only one value of x will produce one value of f(x).
This is quite a complex idea, so let's look at an example.
Using the function x2 the rearrangement gives us,
f−1(x) = ±√x
This would then define a one-to-many mapping and therefore not give a function (as a function cannot be a one-to-many mapping).
Therefore, f: x → x2, x ∈ R does not have an inverse function.
You can obtain the reverse mapping by only allowing x to take positive real numbers (or only negative real numbers).
So we have, f: x → x2, x ∈ R+ which is a one-to-one mapping.
The reverse mapping only allows positive square roots in the range.
So, the inverse is, f−1 :x → √x, where x ∈ R+
As mentioned earlier, all you need to do to sketch the graph of the inverse function f−1 is to reflect f in the line y = x.
However, if f does not have an inverse, you will still be able to reflect the graph, but it will not represent the inverse function.
Example:
Find the inverse function of f(x) ≡ 3x, x ∈ R, and sketch the graph.
To find f−1 we have to map values of 3x back onto the values of x.
Therefore:
for f(x), y = 3x
For f−1(x), x = 3y, and by taking logarithms we get,
f−1(x) ≡ log3x
The curves of the two function are the same, but the inverse function has been reflected in the line y = x. See the diagram below: